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The conductor of an Artin representation is a positive integer that measures its ramification. It can be expressed as a product of local conductors.

Let K/QK/\Q be a Galois extension and ρ:Gal(K/Q)GL(V)\rho:\Gal(K/\Q)\to\GL(V) an Artin representation. Then the conductor of ρ\rho is ppf(ρ,p) \prod_p p^{f(\rho,p)} for non-negative integers f(ρ,p)f(\rho,p), where the product is taken over prime numbers pp.

To define the exponents f(ρ,p)f(\rho,p), fix a prime p\mathfrak{p} of KK above pp and consider the corresponding extension of local fields Kp/QpK_{\mathfrak{p}}/\Q_p with Galois group GG. Then GG has a filtration of higher ramification groups in lower numbering GiG_i, as defined in Chapter IV of Serre's Local Fields [MR:0554237, 10.1007/978-1-4757-5673-9]. In particular, G1=GG_{-1}=G, G0G_0 is the inertia group of Kp/QpK_\mathfrak{p}/\Q_p, and G1G_1 is the wild inertia group, which is a finite pp-group.

Let gi=Gig_i = |G_i|. Then f(ρ,p)=i0gig0(dim(V)dim(VGi)) f(\rho, p) = \sum_{i\geq 0} \frac{g_i}{g_0} (\dim(V) - \dim(V^{G_i})) where VGiV^{G_i} is the subspace of VV fixed by GiG_i.

Note that if pp is unramified in KK, then f(ρ,p)=0f(\rho,p)=0 and conversely, if ρ\rho is faithful and pp is ramified in KK, then f(ρ,p)>0f(\rho,p)>0.

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  • Last edited by John Jones on 2023-04-26 10:22:33
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