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The discriminant Δ\Delta of a Weierstrass equation over a field KK is an element of KK defined in terms of the Weierstrass coefficients. If the Weierstrass equation is y2+a1xy+a3y=x3+a2x2+a4x+a6,y^2+a_1xy+a_3y=x^3+a_2x^2+a_4x+a_6, then Δ\Delta is given by a polynomial expression in a1,,a6a_1,\dots,a_6, namely, Δ=b22b88b4327b62+9b2b4b6\Delta=-b_2^2b_8 - 8 b_4^3 -27 b_6 ^2 + 9 b_2 b_4 b_6 where b2=a12+4a2b4=2a4+a1a3b6=a32+4a6b8=a12a6+4a2a6a1a3a4+a2a32a42.\begin{aligned} b_2 &= a_1^2 + 4 a_2\\ b_4 &= 2a_4 + a_1 a_3\\ b_6 &= a_3^2 + 4 a_6 \\ b_8 &= a_1^2 a_6 + 4 a_2 a_6 - a_1 a_3 a_4 + a_2 a_3^2 - a_4^2. \end{aligned}

Then Δ0\Delta\neq 0 if and only if the equation defines a smooth curve, in which case its projective closure gives an elliptic curve.

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  • Last edited by John Cremona on 2021-01-07 09:43:10
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